An electron emitted by a heated cathode and accelerted through a potential difference of `2.Kv,` enters a region of uniform magnetic field of `0.15T`. Determine the trajectory of the electron if the field is transverse to its invial velocity

Explanation

The trajectory of the electron will be a cricle or radius r with the magnetic field as its axis. The radii r is given by, `r=(mv)/(Be)`
Also `eV=(1)/(2)mv^(2)`
`:. r= (1)/(B)((2mV)/(e))^((1)/(2)) =(1)/(0.15) sqrt((2xx9xx10^(-31)xx2xx10^(3))/(1.6xx10^(-19))`