Determine the polarising angle of the light ray moving from water of refractive index 1.33 to glass of refractive index 1.5.

Explanation

From Brewster's law we have,
`""_(w)mu_(g) = tani_(p)` [here `i_(p)` = polarising angle]
or, `(""_(a)mu_(g))/(""_(a)mu_(w)) = tani_(p) " " or, (1.5)/(1.33) = tan i_(P)`
or, `tani_(p) = 1.13`
or, ` i_(p) = tan^(-1)(1.13) = 48.5^(@)`