Calculate the momentum of a photon of frequency `5 xx 10^(13) Hz`.Given, `h = 6.6 xx 10^(-34)J.s and c = 3 xx 10^(8) m.s^(-1)`

Explanation

de Broglie wavelength, `lamda = (h)/(mv) = (h)/(p)`
`:.` Momentum, `p = (h)/(lamda)`
Therefore, momentum of the photon,
`p = (h)/(lamda) = (hf)/(c) = ((6.6 xx 10^(-34)) xx (5 xx 10^(13)))/(3 xx 10^(8))`
`= 1.1 xx 10^(-28) kg.m.s^(-1)`