thresold Wavelength of incident light on a metal surface is 404 `Å`. Determine the work function.

Einstein's equation for photoelectric effect is E_("max") = hf - W_(0) , where h = Planck's constant = 6.625 xx 10^(-34) J.s, f = frequency of light incident on metal surface, W_(0) = work function of metal and E_("max") = maximum kinetic energy of the emitted photoelectrons. It is evident that if the frequency f is less than a minimum value f_(0) or if the wavelength lamda is greater than a maximum value lamda_(0) , the value of E_("max") would be negative, which is impossible. Thus for a particular metal surface f_(0) is the threshold frequency and lamda_(0) is the threshold wavelength for photoelectric emssion to take place. Again if the collector plate is ketp at a negative potential with respect to the emitter plate, the velocity of the photoelectrons would decrease. The minimum potential for which the velocity of the speediest electron becoes zero, is known as the stopping potential, the photoelectric effect stops for a potential lower than this. [velocity of light = 3xx 10^(8) m.s^(-1) , mass of an electron m = 9.1 xx 10^(-31) kg , charge of an electron, e = 1.6 xx 10^(-19)C The threshold wavelength of photoelectric effect for a metal surface is 4600 Å . Work function of the metal (in eV) is

Threshold wavelength for photoelectric emission from a metal surface is 3800Å , Utraviolet light of wave-length 2600Å is incident on the metal surface. Find the work function of the metal and

Work function for a metal is 1.77 eV and the wavelength of an incident ray on that metal is 5893 Å . Determine the maximum kinetic energy of the photoelectrons emitted from that metal.

The photoelectric threshold wavelength of radiation incident on its surface is 3415 Å . If the wavelength of radiation incident on its surface 2020 Å , find out the (i) work function and (ii) kinetic energy of the fastest photoelectrons.

Stopping poential for the electrons emitted due to incidence of light on a metal is 3V. Determine the frequency of this light and also the work function for metal. Given, the threshold frequency for photoelectric emission from that metal is 6xx10^(14) Hz .

The work function for electron emission from a metal is 1.9 eV, and the wavelength of the radiation incident on its surface is 4041 Å . Find out the kinetic energy of the fastest photoelectrons.

The maximum velocities of the photoelectrons ejected are v and 2v for incident light of wavelength 400 nm and 250 nm on a metal surface respectively. Calculate the work function of the metal. Given h = 6.63 xx 10^(-34)J.s and c = 3 xx 10^(8) m.s^(-1)

The stopping potential of copper is 2.72V for light of wavelength 1849 Å . Determine the work function and threshold frequency of the metal.

Threshold wavelength for photoelectric emission from a metal surface is 3800Å , Utraviolet light of wave-length 2600Å is incident on the metal surface. maximum kinetic energy of emitted photoelectron. (h = 6.63 xx 10^(-27) " erg.s")

Energy of photon incident on a metal plate is twice its work function. How many times should be the wavelength of incident light so that the kinetic energy of the fastest electron will be doubled?