Home
Class 12
PHYSICS
Statement I: A proton, a deutron and an ...

Statement I: A proton, a deutron and an `alpha`-particle are accelerated by the same potential difference. Their velocities will be in the ratio of `1 : 1 : sqrt2`
Statement II: Kinetic energy, `E = qV = (1)/(2) mv^(2)`

A

Statement I is true, statement II is true, statement II is a correct explanation for statement I

B

Statement I is true, statement II is true, statement II is not a correct explanation for statement I

C

statement I is true, statement II is false

D

statement I is false, statement II is true

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • QUANTUM THEORY

    CHHAYA PUBLICATION|Exercise Entrance Corner (Multiple Correct Answer Type)|10 Videos
  • QUANTUM THEORY

    CHHAYA PUBLICATION|Exercise Entrance Corner (Comprehension type)|8 Videos
  • QUANTUM THEORY

    CHHAYA PUBLICATION|Exercise Exercise (Hots Numerical Problems)|4 Videos
  • OPTICAL INSTRUMENTS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|8 Videos
  • QUESTION PAPER OF NEET 2017

    CHHAYA PUBLICATION|Exercise QUESTION PAPERS OF (NEET) (2017)|39 Videos

Similar Questions

Explore conceptually related problems

A proton and an alpha particle are accelerated through the same potential difference. Which one of the two has greater de Broglie wavelength,

A proton and an alpha particle are accelerated through the same potential difference. Which one of the two has less kinetic energy? Justify your answer.

An alpha -particle and a proton are accelerated through the same potential difference. Find the ratio of de Broglie wavelengths.

A proton, a deuteron and an alpha - particle are accelerated by the same potential and then enter a uniform magnetic field perpendicularly. The ratio of radii of their circular paths will be

An alpha -particle and a proton are accelerated from rest through the same potential difference V. Find the ratio of de Broglie wavelengths associated with them.

An alpha -particle and a proton are accelerated from rest thruogh the same potential difference and both enter a uniform perpendicular magnetic field. Find the ratio of their radii of curvature.

Statement I: If a stationary electron is accelerated with a potential difference of 1V, its de Broglie wavelength becomes 12.27 Å approximately. Statement II: The relation between the de Broglie wavelength lamda and the accelerating potential V of an electron is given by lamda = (12.27)/(V) Å

Kinetic energy of proton is the same as that of an alpha -particle. What is the ratio of their respective de Brogile wavelengths?

Two particles have masses m & 4m and their kinetic energies are in the ratio 2: 1 . What is the ratio of their linear momenta?

Statement I : If a proton and an electron are placed in the same uniform electron field, they experience different accelerations. Statement II : Electric force on a test charge is independent of its mass.