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Hydrogen ("1^1H) deuterium ("1^2H), sing...

Hydrogen `("_1^1H)` deuterium `("_1^2H)`, singly ionised helium `("_2^4H)^+` and doubly ionised lithium `("_3^6Li)^(++)` all have one electron around the nucleus. Consider an electron transition from n=2 to n=1 . If the wavelengths emitted radiation are `lambda_1,lambda_2,lambda_3 and lambda_4` respectively then approximately which one of the following is correct?

A

`lambda_1=2lambda_2=3lambda_3=4lambda_4`

B

`4lambda_1=2lambda_2=2lambda_2=lambda_4`

C

`lambda_1=2lambda_2=2lambda_3=lambda_4`

D

`lambda_1=lambda_2=4lambda_3=9lambda_4`

Text Solution

Verified by Experts

The correct Answer is:
D

`1/(lambda)RZ(1/(f^2)-1/(i^2))=RZ^2(1/1^2-1/2^2)=3/4RZ^2`
`therefore lambda prop 1/Z^2`
For hydrogen , Z=1 , for deuterium, Z=1,
for helium ion Z=2 , for lithium ion ,Z=3
`therefore lambda_1 =lambda_2=4lambda_3 =9lambda_4`
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