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What is the equilibrium expression for t...

What is the equilibrium expression for the reaction `P_(4(s)) + 5O_(2(g))hArrP_(4)O_(10(s))` ?

A

`K_C=([P_4O_10])/([P_4][O_2]^5)`

B

`K_C=1/([O_2])^5`

C

`K_C=[O_2]^5`

D

`K_C=([P_4O_10])/(5[P_4][O_2])`

Text Solution

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The correct Answer is:
B
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The equilibrium constant for the reaction? P_(4(s)) +5 O_(2(g)) rarr P_(4)O_(10(s)) (A) k_(p) =(1)/ (p_(o_(2))^(5)) (B) k_(p) = p_(o_(2))^(5) (C) k_(p) = (P_(P_(4)o_(10))) / (p_(p_(4)) p_(o_(2))^(5)) (D) k_(p) = (p_(p_(4)) * p_(o_(2))^(5)) / (P_(p_(4)o_(10))) ]

For the reaction 2NO_(2(g))+(1)/(2)O_(2)hArrN_(2)O_(5(g)) if the equilibrium constant is K_(P) ,then the equilibrium constant for the reaction 2N_(2)O_(5(g))hArr4NO_(2(g))+O_(2(g)) would be :-

GRB PUBLICATION-CHEMICAL EQUILIBRIUM-D.Le Chateliera principle
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