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CO(g)+Cl2(g) hArr COCl(g)+Cl(g) K(eq)=1....

`CO(g)+Cl_2(g) hArr COCl(g)+Cl(g) K_(eq)=1.5xx10^(-39)`
If the rate constant , K, for the forward reaction is `1.4xx10^(-28) L mol^(-1) sec^(-1)` what is K ( in L `mol^(-1) sec^(-1)` ) for the backward reaction ?

A

`2.1xx10^(-67)`

B

`1.0xx10^(-11)`

C

`9.3xx10^(10)`

D

`7.1xx10^(27)`

Text Solution

Verified by Experts

The correct Answer is:
C
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