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The formation constant of Ni(NH3)6^(2+) ...

The formation constant of `Ni(NH_3)_6^(2+)` is `6xx10^8` at `25^@C`.If 50 ml of 2.0 M `NH_3` is added to 50 ml of 0.20 M solution of `Ni^(2+)` , the concentration of `Ni^(2+)` ion will be nearly equal to :

A

`3xx10^(-10) "mole" "litre"^(-1)`

B

`2xx10^(-10) "mole" "litre"^(-1)`

C

`2xx10^(-9) "mole" "litre"^(-1)`

D

`4xx10^(-8) "mole" "litre"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
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