An element undergoes s reaction as show -
`X+2e^(-)``rarrX^(2-)`, energy relesed `=30.87eV//"atom"`. If the energy released ,is used to dissociate 8 gms of `H_(2)` molecules,equally into `H^(+)` and `H^(ast)`,where `H^(ast)` is an exicted state of H atoms where the electron travels in orbit whose circumference equal to four times its de Broglie's wavelenght .
(a) Calculate the excited statue of H
(b) Determine the least amount of X that would be required .
Given : `IE of H = 13.6 eV//"atom"`, Bond energy of `H_(2) =4.526 eV//"molecule"`.

Explanation

(a) ` 2pir=4lambda`
` therefore`` n=4`
(b) `therefore` Total energy required
`=4xx4.526eVxx6.023xx10^(23)+4xx13.6xx6.023xx10^(23)+4xx12.75eVxx6.023xx10^(23)`
`=4xx6.023xx10^(23)[30.876]`
` therefore` moles of X required =4mole