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The energy of an electron in the first B...

The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV`. The possible energy values (s) of the excited state (s) for electron in bohr orbits of hydrogen is (are)

A

`-3.4 eV`

B

`4.2 eV`

C

`-6.8 eV`

D

`+6.8 eV`

Text Solution

Verified by Experts

The correct Answer is:
A
Possible values are `=(13.6)/(n^(2))=-13.6,-(13.6)/(4),-(136.)/(9)`
So 3.4 eV is only possible value in given option is `=(h)/(2pi)`
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