Calculate the number of O-atoms in 0.5 mol of `SO_(2)`.

Explanation

No. of molecules present in 1 mol `SO_(2)=6.022xx10^(23)`.
Number of molecules present in 0.5 mol `SO_(2)`
`=0.5xx6.022xx10^(23)=3.011xx10^(23)`
2 oxygen atoms are present inn each `SO_(2)` molecule.
`therefore` The number of oxygen atoms present in 0.5 mol of `SO_(2)`
`=3.011xx10^(23)xx2=6.022xx10^(23)`.