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Under same conditions of temperature and...

Under same conditions of temperature and pressure the vapour density of an elementary gas is 5 times than that of oxygen. Calculate the relative atomic mass of the gas if it is diatomic in nature.

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Vapour density of oxygen (D)=32/2=16.
`therefore` Vapour density of the gaseous element`=5xx16=80`.
`therefre`Molecular mass of the gaseous element`=2xx80=160`.
`=("molecular mass of the element")/("its atomicity")=(160)/(2)=80`
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