Home
Class 11
CHEMISTRY
Yellow light emitted from a sodium lamp ...

Yellow light emitted from a sodium lamp has a wavelength `(lamda)` of 580 nm. Calculate the frequency (v) and wave number `(overline(v))` of the yellow light.

Text Solution

Verified by Experts

Wavelength, `lamda=580` nm`=580xx10^(-9)m=5.80xx10^(-7)m`
`therefore`Frequency of yellow light,
`v=(c)/(lamda)=(3xx10^(8)m*s^(-1))/(5.80xx10^(-7)m)=5.17xx10^(14)s^(-1)`
[Speed of light, `c=3xx10^(8)m*s^(-1)`]
and wave number, `overline(v)=(1)/(lamda)=(1)/(5.80xx10^(-7)m)`
`=1.72xx10^(6)m^(-1)`.
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    CHHAYA PUBLICATION|Exercise HIGHER ORDER THINKING SKILL (HOTS) QUESTIONS|19 Videos

  • STRUCTURE OF ATOM

    CHHAYA PUBLICATION|Exercise ENTRANCE QUESTION BANK|57 Videos

  • STRUCTURE OF ATOM

    CHHAYA PUBLICATION|Exercise SOLVED WBCHSE SCANNER|27 Videos

  • STATES OF MATTER : GASES AND LIQUIDS

    CHHAYA PUBLICATION|Exercise PRACTICE SET|10 Videos

Similar Questions

Explore conceptually related problems

Yellow light emitted from a sodium lamp has wavelength 580 nm. Calculate the frequency nad wave number of yellow light.

Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength 6800 Å. Calculate threshold frequency (v_(0)) and work function (W_(0)) of the metal.

A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57 mum . Calculate the rate of emissionn of quanta per second.

Calculate the wavelength, frequency and wave-number of a light wave whose period is 2.0xx10^(-10)s .

An 80 watt bulb emits monochromatic light of wavelength 480 nm. Calculate the number of photons emitted per second by the bulb?

A metal has a work function of 2eV. It is illuminated by monochromatic light of wavelength 500 nm, calculate (i) the threshold wavelength, (ii) the maximum energy of photoelectrons, (iii) The stopping potential. Given Planck's constant h = 6.6 xx 10^(-34)J.s , charge on electron e = 1.6 xx 10^(-19) C and 1eV = 1.6 xx 10^(-19)J

Monochromatic light of wavelength 589 nm is incident on a water surface from air the wavelength, frequency and speed of (b) refracted light?

Einstein established the idea of photons on the basis of Planck's quantum theory. According to his idea, the light of frequency f or wavelength lamda is infact a stream of photons. The rest mass of each photon is zero and velocity is equal to the velocity of light (c) = 3 xx 10^(8) m.s^(-1) . Energy, E = hf, where h = Planck's constant = 6.625 xx 10^(-34)J.s . Each photon has a momentum p = (hf)/(c) , although its rest mass is zero. The number of photons increase when the intensity of incident light increases and vice-versa. On the other hand, according to de Broglie any stream of moving particles may be represented by progressive waves. The wavelength of the wave (de Broglie wavelength) is lamda = (h)/(p) , where p is the momentum of the particle. When a particle having charge e is accelerated with a potential difference of V, the kinetic energy gained by the particle is K= eV. Thus as the applied potential difference is increased, the kinetic energy of the particle and hence the momentum increase resulting in a decrease in the de Broglie wavelength. Given, charge of electron, e = 1.6 xx 10^(-19)C and mass = 9.1 xx 10^(-31) kg . The number of photons emitted per second from a light source of power 40 W and wavelength 5893 Å

Einstein established the idea of photons on the basis of Planck's quantum theory. According to his idea, the light of frequency f or wavelength lamda is infact a stream of photons. The rest mass of each photon is zero and velocity is equal to the velocity of light (c) = 3 xx 10^(8) m.s^(-1) . Energy, E = hf, where h = Planck's constant = 6.625 xx 10^(-34)J.s . Each photon has a momentum p = (hf)/(c) , although its rest mass is zero. The number of photons increase when the intensity of incident light increases and vice-versa. On the other hand, according to de Broglie any stream of moving particles may be represented by progressive waves. The wavelength of the wave (de Broglie wavelength) is lamda = (h)/(p) , where p is the momentum of the particle. When a particle having charge e is accelerated with a potential difference of V, the kinetic energy gained by the particle is K= eV. Thus as the applied potential difference is increased, the kinetic energy of the particle and hence the momentum increase resulting in a decrease in the de Broglie wavelength. Given, charge of electron, e = 1.6 xx 10^(-19)C and mass = 9.1 xx 10^(-31) kg . Two stationary electrons are accelerated with potential difference V_(1) and V_(2) respectively such that V_(1) : V_(2) = n . The ratio of their de Broglie wavelength

Einstein established the idea of photons on the basis of Planck's quantum theory. According to his idea, the light of frequency f or wavelength lamda is infact a stream of photons. The rest mass of each photon is zero and velocity is equal to the velocity of light (c) = 3 xx 10^(8) m.s^(-1) . Energy, E = hf, where h = Planck's constant = 6.625 xx 10^(-34)J.s . Each photon has a momentum p = (hf)/(c) , although its rest mass is zero. The number of photons increase when the intensity of incident light increases and vice-versa. On the other hand, according to de Broglie any stream of moving particles may be represented by progressive waves. The wavelength of the wave (de Broglie wavelength) is lamda = (h)/(p) , where p is the momentum of the particle. When a particle having charge e is accelerated with a potential difference of V, the kinetic energy gained by the particle is K= eV. Thus as the applied potential difference is increased, the kinetic energy of the particle and hence the momentum increase resulting in a decrease in the de Broglie wavelength. Given, charge of electron, e = 1.6 xx 10^(-19)C and mass = 9.1 xx 10^(-31) kg . The number of photons emitted per second by a source of light of power 30 W is 10^(20) , the momentum of each photon (in kg.m.s^(-1) )

CHHAYA PUBLICATION-STRUCTURE OF ATOM-SOLVED NCERT EXERCISE
  1. How many neutrons and protons are there in the following nuclei? ""(...

    Text Solution

    |

  2. Write the complete symbol for the atom with the given atomic number (Z...

    Text Solution

    |

  3. Yellow light emitted from a sodium lamp has a wavelength (lamda) of 58...

    Text Solution

    |

  4. Find energy of each of the photons which (1) correspond to light of ...

    Text Solution

    |

  5. Calculate the wavelength, frequency and wave-number of a light wave wh...

    Text Solution

    |

  6. What is the number of photons of light with a wavelength of 4000 pm th...

    Text Solution

    |

  7. A photon of wavelength 4xx10^(-7)m strikes on metal surface, the work ...

    Text Solution

    |

  8. Electromagnetic radiatio of wavelength 242 nm is just sufficient to io...

    Text Solution

    |

  9. A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57m...

    Text Solution

    |

  10. Electrons are emitted with zero velocity from a metal surface when it ...

    Text Solution

    |

  11. What is the wavelength of llight emitted when the electron in a hydrog...

    Text Solution

    |

  12. How much enerrgy is needed to ionise a H-atom if the electron occupies...

    Text Solution

    |

  13. What is the maximum number of emission lines when the excited electron...

    Text Solution

    |

  14. (1) The energy associated with the first orbit in the hydrogen atom is...

    Text Solution

    |

  15. Find the wave number for the longest wavelength transition in the Balm...

    Text Solution

    |

  16. What is the energy in joules, requried to shift the electron of the hy...

    Text Solution

    |

  17. The electron energy is hydrogen atom is given by E"(n)=(-2.18xx10^(-18...

    Text Solution

    |

  18. Calculate the wavelength of an electron moving with a velocity of 2.05...

    Text Solution

    |

  19. The mass of an electron is 9.1xx10^(-31)kg. If its K.E. is 3.0xx10^(-2...

    Text Solution

    |

  20. Which of the following are isoelectronic species i.e., those having th...

    Text Solution

    |