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2xx10^(8) atoms of carbon are arranged s...

`2xx10^(8)` atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrange is 2.4 cm.

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Number of C-atoms `(n)=2xx10^(8)` and length of the arrangement `(l)=2.4cm=2.4xx10^(7)nm`
`therefore`Diameter of carbon atom=l/n. Therefore, radius of carbon atom`=(l)/(2pi)=(2.4xx10^(7)nm)/(2xx2xx10^(8))=0.06` nm
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