Home
Class 11
CHEMISTRY
In astronomical observations, signals ob...

In astronomical observations, signals observed from the distant stars are generally weak. If the photon detector receives a total of `3.15xx10^(-18)J` from the radiations of 600 nm, calculate the number of photons received by the detector.

Text Solution

Verified by Experts

Wavelength, `lamda=600nm=600xx10^(-9)m`
Energy of photon`=(hc)/(lamda)=((6.626xx10^(-34))xx(3xx10^(8)))/(600xx10^(-9))`
`=3.133xx10^(-19)J`
Number of photons detected by the detector
`=("total energy received by the detector")/("energy of each photon")`
`=(3.15xx10^(-18)J)/(3.313xx10^(-19)J)=9.15~~10`photons.
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    CHHAYA PUBLICATION|Exercise HIGHER ORDER THINKING SKILL (HOTS) QUESTIONS|19 Videos
  • STRUCTURE OF ATOM

    CHHAYA PUBLICATION|Exercise ENTRANCE QUESTION BANK|57 Videos
  • STRUCTURE OF ATOM

    CHHAYA PUBLICATION|Exercise SOLVED WBCHSE SCANNER|27 Videos
  • STATES OF MATTER : GASES AND LIQUIDS

    CHHAYA PUBLICATION|Exercise PRACTICE SET|10 Videos

Similar Questions

Explore conceptually related problems

Lifetimes of the molecules in the excited are often measured by using pulsed radiation source of duration nearly in the nano second range. If the radiation source has the duration of 2 ns and the number of photons emitted during the pulse source is 2.5xx10^(15) , calculate the energy of the source.

Calculate the velocity of electron ejected from platinum surface when radiation of 200 nm falls on it. Work function of platinum is 5eV. (1eV=1.6xx10^-19J)

Einstein established the idea of photons on the basis of Planck's quantum theory. According to his idea, the light of frequency f or wavelength lamda is infact a stream of photons. The rest mass of each photon is zero and velocity is equal to the velocity of light (c) = 3 xx 10^(8) m.s^(-1) . Energy, E = hf, where h = Planck's constant = 6.625 xx 10^(-34)J.s . Each photon has a momentum p = (hf)/(c) , although its rest mass is zero. The number of photons increase when the intensity of incident light increases and vice-versa. On the other hand, according to de Broglie any stream of moving particles may be represented by progressive waves. The wavelength of the wave (de Broglie wavelength) is lamda = (h)/(p) , where p is the momentum of the particle. When a particle having charge e is accelerated with a potential difference of V, the kinetic energy gained by the particle is K= eV. Thus as the applied potential difference is increased, the kinetic energy of the particle and hence the momentum increase resulting in a decrease in the de Broglie wavelength. Given, charge of electron, e = 1.6 xx 10^(-19)C and mass = 9.1 xx 10^(-31) kg . The number of photons emitted per second from a light source of power 40 W and wavelength 5893 Å

Emission transitions in the Paschen series end at orbit n=3 and start from orbit n and can be represented as v= 3.29xx10^(15)(Hz)[1//3^(2)-1//n^(2)] . Calculate the value of n if the transition is observed at 1285 nm. Find the region of the spectrum.

Among the photoelectrons, emitted due to incidence of light of frequency f on a metal surface , only the electrons having the highest kinetic energy can ionise a hydrogen atom. If this experment is performed with light of frequency 5/6f , the photoelectron having the highest kinetic energy can excite a hydrogen atom and from this excited hydrogen atom a photon of wavelength 1215 Å is emitted . Determine the (ii) value of f. Given h=6.625 xx10^(-34)*s,c=3xx10^(8)*s^(-1), 1 eV=1.6 xx10^(-19)J , ionisation energy of hydrogen =13.62 eV.

In Young's double slit experiment the coherent sources are 1.5 mm apart and the fringes are obtained on a screen at a distance 2.5 m from the plane of the sources. If the sources is illuminated with a light of 589.3 nm wavelength , find the number of fringes in the interference pattern thus formed on the screen. Total length of the fringes are 4.9 xx 10 ^(-3) m.

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(-13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . The wavelength of radiation emitted for the transition of the electron of He^+ ion from n=4 to n=2 is

CHHAYA PUBLICATION-STRUCTURE OF ATOM-SOLVED NCERT EXERCISE
  1. Nitrogen laser produces a radiatio at a wavelength of 337.1 nm. If the...

    Text Solution

    |

  2. Neon gas is generally used in the sign boards. If it emits strongly at...

    Text Solution

    |

  3. In astronomical observations, signals observed from the distant stars ...

    Text Solution

    |

  4. Lifetimes of the molecules in the excited are often measured by using ...

    Text Solution

    |

  5. The longest wavelength doublet absorption transition is observed at 58...

    Text Solution

    |

  6. The work function for cesium atom is 1.9 eV. Calculate the threshold...

    Text Solution

    |

  7. Following results are observed when sodium metal is irradiated with di...

    Text Solution

    |

  8. The ejection of the photoelectron from the silver metal in the photoel...

    Text Solution

    |

  9. If the photon of the wavelength 150 pm strikes an atom and one of its ...

    Text Solution

    |

  10. Emission transitions in the Paschen series end at orbit n=3 and start ...

    Text Solution

    |

  11. Calculate the wavelength for the emission transition if it starts from...

    Text Solution

    |

  12. Dual behaviour of matter proposed by de Broglie the discovery of elect...

    Text Solution

    |

  13. Similar to electron diffraction, neutorn diffraction microscope is als...

    Text Solution

    |

  14. if the velocity of the electron in Bohr's first orbit is 2.19xx10^(6)m...

    Text Solution

    |

  15. The velocity associated with a proton moving in a potential difference...

    Text Solution

    |

  16. If the position of the electron is measured within an accuracy of +-0....

    Text Solution

    |

  17. The quantum numbers of six electrons are give below. Arrange them in o...

    Text Solution

    |

  18. The bromine atom possesses 35 electrons. It contains 6 electrons in 2p...

    Text Solution

    |

  19. Among the following pairs of orbitals which orbital will experience th...

    Text Solution

    |

  20. The unpaired electrons in Al and Si are present in 3p orbital. Which e...

    Text Solution

    |