The velocity associated with a proton moving in a potential difference of 1000 V is `4.37xx10^(5)m*s^(-1)`. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.

Explanation

Velocity of hockey bal`=4.37xx10^(5)m*s^(-1)`,mass=0.1kg
`therefore`Wavelength `(lamda)=(h)/(mv)=(6.626xx10^(-34)kg*m^(2)*s^(-1))/(0.1kgxx4.37xx10^(5)m*s^(-1))`
`=1.52xx10^(-38)m`