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Let `f(x)` be a real valued continuous function on `R` defined as `f(x)=x^2e^(-|x|)` The value of `k` for which the curve `y=k x^2(k >0)` intersect the curve `y=e^(|x|)` at exactly two points, is `e^2` (b) `(e^2)/2` (c) `(e^2)/4\ ` (d) `(e^2)/8`

A

`(e^(2))/4ltkltoo`

B

`(e^(2))/2`

C

`(0ltklt=4)/(e^(2))`

D

`(e^(2))/4`

Text Solution

Verified by Experts

The correct Answer is:
A, D

Graph of `f(x)`
`y=kx^(2)` will intersect `y=e^(|x|)`
Then `kx^(2)=e^(|x|)`
`x^(2)e^(|x|)=1/kimplies1/k=4/(e^(2))impliesk=(e^(2))/4`
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