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lim(xrarr(pi)/2)(1-sinxsin3xsin5x.sin7x)...

`lim_(xrarr(pi)/2)(1-sinxsin3xsin5x.sin7x)/(((pi)/2-x)^(2))` is `k` then `k/6` equal to

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The correct Answer is:
7
`x-(pi)/2=y`
`lim_(yrarr0) (1-cosycose3ycos5ycos7y)/(y^(2))`
`lim_(yrarro) ((sinycos3ycos5ycos7y+3cosysin3ycos5ycos7y),(+5cosycos3ysin5ycos7y+7cosycos3ycos5ysin7y))/(2y)`
`1/2+9/2+25/2+49/2=42`
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