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sin^(-1)(sin10) is a+bpi then |a+b| is...

`sin^(-1)(sin10)` is `a+bpi` then `|a+b|` is

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Verified by Experts

The correct Answer is:
7
Since `3pilt10lt3pi+(pi)/2` therefore
`0lt10-3pilt(pi)/2implies-(pi)/2lt3pi-10lt0`
So `3pi-10`
`a=-10,b=3`
`implies|a+b|=7`
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