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Find the locus of the point of intersect...

Find the locus of the point of intersection of the perpendicular tangents of the curve `y^2+4y-6x-2=0` .

A

`2x-1=0`

B

`2x+3=0`

C

`2y+3=0`

D

`2x+5=0`

Text Solution

Verified by Experts

The correct Answer is:
D
Given equation reduces to `Y^(2)=6x` where `x+1=X` and `y+2=Y`
`implies` Locus is directrix
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