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If g(x) is monotonically increasing and ...

If g(x) is monotonically increasing and f(x) is monotonically decreasing for x R and if (gof) (x) is defined for x e R, then prove that (gof)(x) will be monotonically decreasing function. Hence prove that` (gof) (x +1)leq (gof) (x-1). `

A

`g(f(ax+1))gtg(f(ax-1))` if `alt0`

B

`g(g(ax+1)gtg(g(ax-1))` if `alt0`

C

`g(f(ax+1)ltg(f(ax-1))` if `agt0`

D

`g(g(ax+1))gtg(g(ax-1))` if `agt0`

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