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The general solution of |sinx|=cosx is (...

The general solution of `|sinx|=cosx` is (When `ninz`) given by

A

`2npi+(pi)/4,n epsilonI`

B

`npi+(pi)/4,n epsilonI`

C

`2npi+-(pi)/4epsilonI`

D

`npi+-(pi)/4,n epsilonI`

Text Solution

Verified by Experts

The correct Answer is:
C
`|sinx|=cosx,` R.H.S.` ge0:.x` will lie either in the first quadrant or fourth quadrant and they are equal for `x=pi//4` or `(7pi)/4`. Therefore general solution is `2npi+-(pi)/4`
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