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sum(r=1)^(n) 1/(log(2^(r))4) is equal to...

`sum_(r=1)^(n) 1/(log_(2^(r))4)` is equal to

A

`(n(n+1))/2`

B

`(n(n+1)(2n+1))/12`

C

`1/(n(n+1))`

D

`(n(n+1))/4`

Text Solution

Verified by Experts

The correct Answer is:
D
`sum_(r=1)^(n)1/(log_(2^(t))4)1/(1/rlog_(2)^(4))=r/2`
`sum_(r=1)^(n) r/2=1/2(1+2+3+……+n)=(n(n+1))/4`
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