At `25^@C` and 760 mm of HG pressure a gas occupies 600 mL volume. What will be its pressure at a height where temperature is `10^@C` and volume of the gas is 640 mL.

Explanation

`p_1=760 mm Hg, V_1=600 mL`
`T_1=25+273=298 K`
`V_2=640 mL and T_2=10+273=283 K`
According to combined gas law
`(p_1V_1)/T_1=(p_2V_2)/T_2`
`impliesp_2=(p_1V_1T_2)/(T_1V_2)`
`impliesp_2((760mmHg)times(600mL) times(283 K))/((640mL) times (298K))`
=676.6 m m Hg