Home
Class 12
CHEMISTRY
Carbon dioxide and another gas 'X' have ...

Carbon dioxide and another gas 'X' have their rates of diffusion as 0.299 cc `s^-1` and 0.271 cc `s^-1` respectively. Find the vapour density of the gas 'X' if the vapour density of carbon dioxide is 22.

Text Solution

Verified by Experts

`("Rate of dif fusion of" CO_2)/("Rate of dif fusion of gas" 'X')=sqrt((V_dof gas 'X')/(V_dof CO_2))`
`=(0.290 c c s^-1)/(0.271 c c s^-1)=sqrt((V_d of gas 'X')/22)`
`V_d of gas 'X'=(0.290 times0.290 times22)/(0.271 times0.271)=25.19`
Promotional Banner

Topper's Solved these Questions

  • STATES OF MATTER : GASES AND LIQUIDS

    VGS PUBLICATION-BRILLIANT|Exercise PROBLEMS|30 Videos

  • ORGANIC CHEMISTRY

    VGS PUBLICATION-BRILLIANT|Exercise Long Answer Questions|67 Videos

  • STOICHIOMETRY

    VGS PUBLICATION-BRILLIANT|Exercise ADDITIONAL QUESTIONS & ANSWERS|10 Videos

Similar Questions

Explore conceptually related problems

Rate of diffusion of carbon dioxide is 2.9 cc s^(-1) and another unknown gas is 2.71 cc s^(-1) . Calculate the vapour density of unknown gas.

Under the same conditions the rates of diffusion of two gases are in the ratio 1:4. The ratio of their vapour densities is

The rate constants of a reaction at 500 K and 700 K are 0.02 s^(-1)and 0.04 s^(-1) respectively. Calculate the values of E_(a) and A.

Helium diffuses 4 times faster than an unknown gas under similar conditions. Find the vapour density of unknown gas.

If the kinetic energy and RMS speed of a gas at a certain temperature are 4 . 0 kJ mol^(-1) 5 . 0 xx 10^(4) cm s^(-1) respectivley . The molecular weight of the gas is

Two gases have densities 0.388g/cc and 0.097gm/cc. If the second gas has the rate of diffusion 5cc/sec, find the rate of duffusion of the first gas.

Two gases have densities 0.388 g L^(-1) and 0.097 g L^(-1) . What is the rate of diffusion of the first gas, if the second gas diffuses at the rate 10 cc s^(-1) under similar conditions ?