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A neon dioxide mixture contains 70.6 g d...

A neon dioxide mixture contains 70.6 g dioxygen and 167.5 g neon. If pressure of the mixture of gases in the cylinder is 25 bar. What is the partial pressure of dioxygen and neon in the mixture?

Text Solution

Verified by Experts

Number of moles of dioxygen = `(70.6g)/(32 g mol^-1)` =2.21 mol
Number of moles of neon =`(167.5g)/(20gmol^-1)`
=8.375 mol
Mole fraction of dioxygen=`2.21/(2.21+8.375)=2.21/10.585=0.21`
Mole fraction of neon =`8.375/(2.21+8.375)=0.79`
Alternatively,
Mole fraction of neon=1-0.21=0.79
Partial pressure =mole fraction `times ` total pressure
`implies` Partial pressure of oxygen
=`0.21 times (25 b ar)=5.25 b ar`
Partial pressure of neon
=0.79 `times ` (25 Bar)=19.75 bar
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