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Calculate kinetic energy of 5 moles of N...

Calculate kinetic energy of 5 moles of Nitrogen at `27^@C`.

Text Solution

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Kinetic energy=`3/2nRT`
where n=5 moles, R=`8.314 mol^-1 k^-1`
`T=27^@C+273=300k`
Kinetic energy
`E_k=3/2times5mol times8.314Jmol^-1K^-1times300K`
=18706.50 J
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