A block of mass 5 kg initially at rest the origin is acted on by a force along the X - positive direction represented by F = (20+5x) N. Calculate the work done by the force during the displacement of the block from x = 0 to x = 4 m .

Explanation

Mass of block , m = 5 kg
Force acting on the block , F = (20+5x)N
If 'w' is the total amount of work done to displace the block from x = 0 to x = 4 m then ,
`W=intdW=int_(x=0)^(x=4)fdx=int_(x=0)^(x=4)(20+5x)dx`
`=[20x+(5x^(2))/(2)]_(0)^(4)=[20xx4-0+(5)/(2)xx(4)^(2)-0]`
rArrW=80+40=120J`