If you shine ultraviolet light on an isolated metal plate, the plate emtis electrons for a while. Why does it eventually stop?

Consider the situation of the previous problem. Consider the fastest electron emitted parallel to the large metal plate. Find the displacement of this electron parallel to its initial velocity before it strikes the large metal plate.

When ultraviolet rays incident on metal plate then photoelectric effect does not occur, it occurs by incidence of : -

A beam of ultraviolet light is incident on the metal ball of an electroscope that is initially uncharged. Does the electroscope acquire a charge?

When ultraviolet rays are incident on a photosensitive metal plate, photoemission is not possible. But it is possible by the incidence of

When a parallel plate capacitor is charged by connecting it across a battery then battery is disconnected. If one plate of capacitor is earthed and isolated then another plate is connected to earth and then isolated. What will be the final charge on the capacitor after this operation. Will it be less than, equal to or more than the initial charge? Explain why?

A dielectric is inserted between the plates of an isolated fully-charged capacitor. The dielectric completely fills the space between the plates. The magnitude of electrostatic force on either metal plate decreases, as it was before the insertion of dielectric medium. Due to insertion of dielectric slab in an isolated parallel plate capacitor (the dielectric completely fills the space between the plates), the electrostatic potential energy of the capacitor decreases.