The photoelectros emitted by an illuminted surface have a maximum kinetic energy of 3.0 eV. If the intensity of the light is tripled, What is the maximum kinetic energy of photoelectrons now?

In photoelectric effect if the intensity of light is doubled then maximum kinetic energy of photoelectrons will become

The maximum kinetic energy of the photoelectrons depends only on

If the frequency of light in a photoelectric experiment is double then maximum kinetic energy of photoelectron

At stopping potential, the kinetic energy of emitted photoelectron is

When monochromatic light of wavelength 620 nm is used to illuminate a metallic surface, the maximum kinetic energy of photoelectrons emitted is 1 eV. Find the maximum kinetic energy of photoelectron emitted (in eV) if a wavelength of 155 nm is used on the same metallic surface. (hc = 1240 eV-nm)

When photons of energy hv fall on a metal plate of work function ' W_(0) ' , photoelectrons of maximum kinetic energy 'K' are ejected. If the frequency of the radiation is doubted, the maximum kinetic energy of the ejected photoelectrons will be

When photons of energy hv fall on an aluminium plate (of work function E_(0) ), photoelectrons of maximum kinetic energy K are ejected . If the frequency of the radiation is doubled , the maximum kinetic energy of the ejected photoelectrons will be

What does the maximum kinetic energy (or the maximum speed) of a photoelectron depend on ?