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The slope of the stopping potential vers...

The slope of the stopping potential versus frequency graph for photoelectric effect is equal to:

A

h

B

he

C

`h//e`

D

e

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The correct Answer is:
To solve the question regarding the slope of the stopping potential versus frequency graph in the photoelectric effect, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Stopping Potential**: The stopping potential (V₀) is the potential required to stop the photoelectrons emitted from a surface when illuminated by light of frequency (ν). It is related to the kinetic energy of the emitted electrons. 2. **Kinetic Energy Relation**: The kinetic energy (KE) of the emitted electrons can be expressed as: \[ KE = eV₀ \] where \(e\) is the charge of the electron. 3. **Energy from Light**: According to the photoelectric effect, the energy of the incoming photons can be expressed as: \[ E = hν \] where \(h\) is Planck's constant and \(ν\) is the frequency of the incident light. 4. **Photoelectric Equation**: The energy conservation principle leads to the equation: \[ hν = W + eV₀ \] where \(W\) is the work function of the material. 5. **Rearranging the Equation**: Rearranging the above equation gives: \[ eV₀ = hν - W \] or \[ V₀ = \frac{h}{e}ν - \frac{W}{e} \] 6. **Identifying the Slope**: The equation \(V₀ = \frac{h}{e}ν - \frac{W}{e}\) resembles the linear equation \(y = mx + c\), where: - \(y\) is the stopping potential \(V₀\), - \(x\) is the frequency \(ν\), - \(m\) (the slope) is \(\frac{h}{e}\), - \(c\) (the y-intercept) is \(-\frac{W}{e}\). 7. **Conclusion**: Therefore, the slope of the stopping potential versus frequency graph is: \[ \text{Slope} = \frac{h}{e} \] ### Final Answer: The slope of the stopping potential versus frequency graph for the photoelectric effect is equal to \(\frac{h}{e}\). ---
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