Ultraviolet light of wavelength `800 A` and `700 A` when allowed to fall on hydrogen atoms in their ground states is found to liberate electrons with kinetic energies `1.8eV` and `4.0eV`, respectively. Find the value of Planck's constant.

Ultraviolet light of wavelengths lambda_(1) and lambda_(2) when allowed to fall on hydrogen atoms in their ground state is found to liberate electrons with kinetic energy 1.8 eV and 4.0 eV respectively. Find the value of (lambda_(1))/(lambda_(2)) .

U.V. light of wavelenght 800Å & 700Å falls on hydrongen atoms in thir ground state & liberates electrons with kinetic energy 1.8eV and 4eV respectively . Calculate planck 's constant.

U.V . light of wavelength 800A^(@)&700A^(@) falls on hydrogen atoms in their ground state & liberates electrons with kinetic energy 1.8eV and 4eV respectively. Calculate planck's constant.

Ultraviolet light of wavelength lambda_(1) and lambda_(2) (with lambda_(2) gt lambda_(1) ) when allowed to fall on hydrogen atoms in their ground state is found to liberate electrons with kinetic energies E_(1) and E_(2) respectively. The value of the planck's constant can be found from the relation

The total energy of the electron in the hydrogen atom in the ground state is -13.6 eV. Which of the following is its kinetic energy in the first excited state?

A photon of energy 10.5eV is allowed to interact with a hydrogen atom in its ground state. Then :

The total energy of the electron in the hydrogen atom in the ground state is - 13.6 eV . The KE of this electron is.

(a) A gas of hydrogen atoms is their ground state is bombarded by electrons with kinetic energy 12.5 ev. What emitted wavelengths would you expect to see? (b) What if the electrons were replaced by photons of same anergy?.

An electron with kinetic energy =E eV collides with a hydrogen atom in the ground state. The collision will be elastic

Total energy of an electron in the hydrogen atom in the ground state is -13.6 eV. The potential energy of this electron is