Find the frequency of light which ejects electrons from a metal surface. Fully stopped by a retarding potential of `3 V`, the photoelectric effect begins in this metal at a frequency of `6xx10^(14)Hz`. Find the work function for this metal. (Given `h=6.63xx10^(-34)Js`).

Find the frequency of light which ejects electrons from a metal surface , fully stopped by a retarding potential of 3.3 V. If photo electric emission begins in metal at a frequency of 8xx10^(14)Hz , calculate the work function (in eV) for this metal.

The minimum frequency for photoelectric effect on a metal is 7xx10^(14) Hz, Find the work function of the metal.

Electrons ejected from the surface of a metal, when light of certain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begains at a frequency 6xx10^(14)s^(-1) . The frequency of the incident light in s^(-1) is [h=6 x10^(-34) J-sec , charge on the electron = 1.6xx10^(-19)C ]

Find the frequency of light incident on a metal surface if the photocurrent is brought to zero by a stopping potential of 2.6V . The threshold frequency for the metal surface is 5xx10^(14)//s .

If a photoemissive surface has a threshold frequency of . 6 xx 10^(14)Hz , calculate the energy of the photons in eV. Given h=6.6 xx 10^(-34)Js .

The threshold frequency for a photosensitive metal is 3xx10^(14)Hz . The work function of the metal is approximately equal to [h=6.66xx10^(-34)Js]

Light of frequency 10^(15) Hz falls on a metal surface of work function 2.5 eV. The stopping potential of photoelectrons in volts is

The threshold wavelength for the ejection of electrons from the metal X is 330 nm. The work function for the photoelectric emission for metal X is (h = 66 xx 10^(-34) Js)