When a metal plate is exposed to a monochromatic beam of light of wavelength 400nm, a negative potential of 1.1 V is needed to stop the photocurrent . Find the threshold wavelength for the metal.

Light of wavelength 450 nm is incident on a metal , and it is found that negative potential of 1 V is needed to stop the photocurrent completely. What is the threshold wavelength of the material ?

Light of wavelength 450 nm in incident on a metal , and it is found that negative potential of 1 V is needed to stop the photocurrent completely. What is the threshold wavelength of the material ?

When light of wavelength lambda is incident on a metal surface, stopping potential is found to be x. When light of wavelength n lambda is incident on the same metal surface, stopping potential is found to be (x)/(n+1) . Find the threshold wavelength of the metal.

When a metallic surface is illuminated with monochromatic light of wavelength lambda , the stopping potential is 5 V_0 . When the same surface is illuminated with the light of wavelength 3lambda , the stopping potential is V_0 . Then, the work function of the metallic surface is

When a metallic surface is illuminated with monochromatic light of wavelength lambda , the stopping potential is 5 V_0 . When the same surface is illuminated with light of wavelength 3lambda , the stopping potential is V_0 . If work function of the metallic surface is

When a metallic surface is illuminated with monochromatic light of wavelength lambda , the stopping potential is 5 V_0 . When the same surface is illuminated with light of wavelength 3lambda , the stopping potential is V_0 . Then the work function of the metallic surface is:

When a metal surface is illuminated by a monochromatic light of wave-length lambda , then the potential difference required to stop the ejection of electrons is 3V . When the same surface is illuminated by the light of wavelength 2lambda , then the potential difference required to stop the ejection of electrons is V . Then for photoelectric effect, the threshold wavelength for the metal surface will be

When a metallic surface is illuminated with monochromatic light of wavelength X, the stopping potential is 5Vq. When the same surface is illuminated with light of wavelength 3X, the stopping potential is Then the work function of the metallic surface is

When a metallic surface is illuminated with monochromatic light of wavelength lambda ,the stopping potential is 5V_(0) .When the same surface is illuminated with light of wavelength 3 lambda ,the stopping potential is V_(0) .The work function of the metallic surface is (hc)/(n lambda) .Find n ?