A stationary hydrogen atom emits a photon corresponding to first line of the Lyman series. What velocity does the atom acquire?

A stationary hydrogen atom emits a photon corresponding to the first line of the Lyman series. What is the velocity of recoil of the atom? (m_(H)=1.672xx10^(-27) kg)

A stationary hydrogen atom emits photn corresponding to the first line of Lyman series. If R is the Rydberg constant and M is the mass of the atom, then the velocity acquired by the atom is

A stationary helium ion emits a photon corresponding to the first line of Lyman series. That photon liberates a photoelectron form a stationary hydrogen atom in ground state. Find the velocity of photoelectron. Take mass of electron =9.11xx10^(-31)kg and ionisation energy of hydrogen atom=13.6ev.

[" A stationary "He'" ion emitted a photon corresponding to the first line of the lyman series.The "],[" photon liberates electron from a stationary hydrogen atom in the ground state.The velocity of "],[" the liberated electron is "3.1times10^(@)m/s" .Find "x" (you can make necessary approximations) "],[" [Here by lyman series it is meant that transition is from "n=2" to "n=1" for "He^(+)]]

stationary He^(o+) ion emits a photon corresponding to the first line (H_(4)) of the lyman series .The photon than emitted strikles a if atom in the ground state .Find the velocity of the photoelectron ejected out of the hydrogen atom .The value of R is 1.097 xx 10^(7)m^(-1)

A hydrogen atom of mass m emits a photon corresponding to the fourth line of Brackett series and recoils. If R is the Rydberg's constant and h is the Planck's constant, then recoiling velocity is

Whenever a hydrogen atom emits a photon in the Balmer series