Consider the fission reaction
`.^(235)U+nrarrX+Y+2n`
Rank the following possible nuclides for representation by X (orY), most likely first:
(a) `.^(152)Nd`, (b) `.^(140)I`, (c) `.^(128)In`, (d) `.^(115)Pd`, (e) `.^(105)Mo`

A generic fission event is ""^(235)U+ntoX+Y+2n Which of the following pairs cannot represent X and Y: (a) ""^(141)Xe and ""^(93)Sr (b) ""^(139)Cs and ""^(94)Rb (c) ""^(156)Nd and ""^(79)Ge d. ""^(121)"In" and ""^(113")Ru ?

Which of the following is correct regarding nuclear fission? (i) The process in which a heavy nucleus is broken into two nearly equal fragments, is called ‘Nuclear Fission’ (ii) Nautral uranium has two istopes, ._(92)U^(238) and ._(92)U^(235) in the ratio 1 : 0.07 . the fission of U^(235) takes place only by fats neutrons, whereast that of U^(235) is possible by slow neutrons (iii) One of the reaction for fission of U^(235) ._(92)^(236)U+._(0)^(1)nrarr._(92)^(236)Urarr._(52)^(144)Ba+._(36)^(89)Kr+3_(0)^(1)n + energy (iv) In the fission of one U^(235) nucleus, about 200MeV of enegry of obtained. Most of this enegry is obtained from of K.E. of fragments obtained by fission, the rest of obained as K.E. of emitted neutrons, gamma -rays, heat and light radiation

Considering X axis as the internuvlear axis, which out of the following will form a sigma bond (a) 1s and ls (b) ls and 2p_(x) (c ) 2p_(y) and 2p_(y) (d) 2p_(x) and 2p_(y) (e) 1s and 2s .

If y=sqrt(logx+sqrt(logx+sqrt(logx+oo))),t h e n(dy)/(dx)i s (a) x/(2y-1) (b) x/(2y+1) (c) 1/(x(2y-1)) (d) 1/(x(1-2y))

Using the Leibnitz formula give the derivatives of the indicated orders for the following functions (a) y=x^(3) sin x , find y^(20) (b) y=e^(-x) sin x , find y''', (c ) y=e^(x)(3x^(2)-4) , find y^(n) (d) y=(1-x^(2))cos x , find y^(2n)

Consider the following equations for a cell reaction A+BiffC+D, E^(@)=x"volt",K_(eq)=K_1 2A+2Biff2C+2D, E^(@)=y"volt",K_(eq)=K_2 then:

Consider the following equations for a cell reaction, A + B rarr C + D , E^(@) = x "volt", Delta G= Delta G_(1) 2A + 2B rarr 2C + 2D, E^(@) = y "volt", DeltaG = DeltaG_(2) Then,