find maximum height reached by small mass m in fig 4E.24

Derive an expression to find out the maximum height reached by a particle when it is thrown upward with a velocity u.

A ball is thrown vertically upwards with a velocity of 4.9m/s Find (i) the maximum height reached by the ball (ii) time taken to reach the maximum height

A ball is thrown up at a speed of 4.0 m/s. Find the maximum height reached by the ball. Take g=10 m//s^2 .

Find the maximum height reached by a particle which is thrown vertically upwards with the velocity of 20 m//s (take g= 10 m//s^(2) ).

Two stones are projected with the same speed but making different angles with the horizontal. Their horizontal ranges are equal. The angle of projection of one is pi/3 and the maximum height reached by it is 102 m. Then the maximum height reached by the other in metres is

A sphere of mass m collides against a pendulum of mass m with horizontal velocity upsilon_90) . (i) Calculate the maximum height reached by the pendulum if the masses scatter elastically along the line of initial motion, (ii) What is the maximum height reached by the pendulum if the two masses stick together ?

Two particles of equal mass are projected simultaneously with speeds 20 m//s end 10sqrt(3)m//s as shown in figure. Find the maximum height reached by the centre of mass of the particles

The maximum height reached by projectile is 4 m . The horizontal range is 12 m . The velocity of projection in m s^-1 is (g is acceleration due to gravity)

A body projected with some velocity passes 2 points at the same height at the instant 2 seconds and 4 seconds. The maximum height reached by the body is (A) 44.1m (B) 24.1m (C) 22m (D) None

A mass of 10 gm moving with a velocity of 100 cm / s strikes a pendulum bob of mass 10 gm . The two masses stick together. The maximum height reached by the system now is (g=10m//s^(2))