A board of mass m = 1 kg lies on a table and a weight of M = 2 kg on the board. What minimum force F must be applied on the board in order to pull it out from under the road ? The coefficient of friction between board and table is `mu_(2) = 0.5` : (Take `g = 10 m//s^(2)`)

A rough vertical board has an acceleration a so that a 2 kg block pressing against it dows not fall. The coefficient of friction between the block and the board should be

A horizontal force of 20 N i sapplied to a block of mass 4 kg resting on a rough horiozontal table. If the blcok does not move on the table, how much fricrtional force the table is applying on the blockgt What can be said about the coefficient of static friction between the block and the table? Take g=m/s^2 .

A force of 200N is applied as shown in the figure on block of 3 kg. The coefficient of friction between the block and the wall is 0.3. Find the friction acting on the block. (in N) {Take g = 10 m//s^(2)

A force F is applied on a block of mass 5 kg as shown in figure. Co-efficient of friction between the wall and clock is (sqrt(3))/(2). (g = 10m//s^(2)) Select correct option(s)

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 3 N is applied on the block as shown in figure. The force of friction between the block and the floor is (Take g=10 m s^(-2) )

Find the minimum force F_0 that should be applied to the block of mass m = 0.5 kg so that the block stays in equilibrium with the rough vertical wall having friction coefficient mu = 0.2 (Take g = 10 m/s^2 )

In the given system, a block of mass m is resting on a board which makes an angle theta with the horizontal. What should be the minimum value of theta , so that the block just starts moving downwards? The coefficient of friction between the surfaces of the board and the block is mu .

A body of mass 2 kg at rest on a horizontal table. The coefficient of friction between the body and the table is 0.3 . A force of 5N is applied on the body. The force of friction is

A block of mass 50 kg slides over a horizontal distance of 1m. If the coefficient of friction between their surface is 0.2, then work done against friction is (take g = 9.8 m//s^(2) ) :

A rectangular block of mass 5 kg is kept on a horizontal surface . The coefficient of friction between the block and the surface is 0.2 . If a force of 20 N is applied to the block at angle of 30^(@) with the horizontal plane , what is the force of friction on the block ? (Take g = 10 m//s^(2) )