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For the reaction, 2Fe(NO3)+3Na2COrarrFe2...

For the reaction, `2Fe(NO_3)+3Na_2COrarrFe_2(CO_3)_3+6NaNO_3` initially `2.5` mole of `Fe(NO_3)_3 and 3.6` mole of `Na_2 CO_3` are taken. If `6.3` mole of `NaNO_3` is obtained then % yield of given reaction is :

A

50

B

84

C

87.5

D

100

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