The standard free energy change of a reaction is `DeltaG^(@)=-kJ//mol^(-1)` at `298 K.` Calculate the value of `log_(10)K_(p)` `(R=8.314JK^(-1)mol^(-1))`
A
`20.16`
B
`2.303`
C
`2.016`
D
`13.83`
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The correct Answer is:
A
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