For the reaction `C_(2)H_(6)(g)hArrC_(2)H_(4)(g)+H_(2)(g)` `K_(p)` is `5xx10^(-2)` atm. Calculate the mole per cent of `C_(2)H_(6)(g)` at equilibruium if pure `C_(2)H_(6)` at `1` atm is passed over a suitable catalyt at `900 K` :
A
`20`
B
`33.33`
C
`66.66`
D
None of these
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The correct Answer is:
C
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