For a gaseous reaction `aA(g)+bB(g)hArrcC(g)+dD(g)` equilibrium constants `K_(c),K_(p)` and `K_(x)` are represented by the following reation `K_(c)=([C]^(c)[D]^(d))/([A]^(a)[B]^(b)),K_(p)=(Pc^(c).P_(D)^(d))/P_(A)^(a)` and `Kx=(x_(C)^(c).x_(D)^(d))/(x_(A)^(a).x_(B)^(b)` where `[A]` represents molar concentrationof `A,p_(A)` represents partial pressure of A and P represents total pressure, `x_(A)` represents mole fraction of A On the basis of above work-up select the write option
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For a gaseous reaction aA(g)+bB(g)hArrcC(g)+dD(g) equilibrium constants K_(c),K_(p) and K_(x) are represented by the following reation K_(c)=([C]^(c)[D]^(d))/([A]^(a)[B]^(b)),K_(p)=(Pc^(c).P_(D)^(d))/P_(A)^(a) and Kx=(x_(C)^(c).x_(D)^(d))/(x_(A)^(a).x_(B)^(b) where [A] represents molar concentrationof A,p_(A) represents partial pressure of A and P represents total pressure, x_(A) represents mole fraction of For the following equilibrium relation betwen K_(c) and K_(c) (in terms of mole fraction) is PCl_(3)(g)+Cl_(2)(g)hArrPCl_(5)(g)
For a gaseous reaction aA(g)+bB(g)hArrcC(g)+dD(g) equilibrium constants K_(c),K_(p) and K_(x) are represented by the following reation K_(c)=([C]^(c)[D]^(d))/([A]^(a)[B]^(b)),K_(p)=(Pc^(c).P_(D)^(d))/P_(A)^(a) and Kx=(x_(C)^(c).x_(D)^(d))/(x_(A)^(a).x_(B)^(b) where [A] represents molar concentrationof A,p_(A) represents partial pressure of A and P represents total pressure, x_(A) represents mole fraction of A For the reaction SO_(2)Cl_(2)(g)hArrSO_(2)(g)+Cl_(2)(g),K_(p)gtK_(x) is obtained at :
Assertion : For a gaseous reaction : 2B to A , the equilibrium constant K_p is less than K_c . Reason: K_p is related to K_c as K_p=K_c(RT)^(Deltan_g)
For the reaction, A(g)+B(s)hArrC(g)+D(g).K_(c)=49 mol L^(-1)at 127^(@)C. Calculate k_(p).
For the reversible reaction A(g)+B(s) hArr 2C(g),K_p/K_c=(RT)^x . Hence x is :
For the reaction SO_(2(g))+(1)/(2)O_(2(g))hArrSO_(3(g)) , if K_(c)=K_(p)(RT)^(X) then the value of X is