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Figure-2.54 shows a block of mass m is p...

Figure-2.54 shows a block of mass m is placed on an inclined wedge of mass M If the system is released from rest find the acceleration of m and M.

Answer

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Figure-2.64 shows a block of mass M supporting a bar of mass m through a pulley system. If system is released from rest, find the acceleration of block M and the tension in the strings

In the system shown in the figure all surfaces are smooth, pulley and string are massless. The string between the two pulleys and between pulley and block of mass 5 m is parallel to the incline surface of the block of mass 4 m. The system is released from rest. Find the acceleration of the block of mass 4 m . ["tan" 37^(@) = (3)/(4)]

Knowledge Check

  • In fig. mass m is being pulled on the incline of a wedge of mass M. All the surfaces are smooth. Find the acceleration of the wedge.

    A
    `a=(F(1-cos theta)mg 2sin theta cos theta)/(M+2m sin^(2)theta)`
    B
    `a=(F(1+cos theta)+mg sin theta cos theta)/(M+m sin^(2)theta)`
    C
    `a=(F(1-cos theta)-mg sin theta cos theta)/(M+m sin^(2)theta)`
    D
    `a=(F(1+cos theta)-mg sin theta cos theta)/(M-m sin^(2)theta)`

  • Figure shown a block of mass m placed on a smooth wedge of mass M. Calculate the minimum value of M' and tension in the string, so that the block of mass m will move vertically downwards with acceleration 10ms^(-2)

    A
    The value of M' is `(Mcot theta)/(1-cot theta)`
    B
    The value of M' is `(M tan theta)/(1-tan theta)`
    C
    The value of tension in the string is `(Mg)/(tan theta)`
    D
    The value of tension is `(Mg)/(cot theta)`

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    In the Fig. shown, mass 'm' is being pulled on the incline of a wedge of mass M. All the surface are smooth. Find the acceleration of the wedge.

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