Find the weight shown by the weighing machine on which a man of mass m is standing at rest relative to it as shown in figure-2.59. Assume that the wedge of mass M is in free fall.

Find the reading of spring balance as shown in figure-2.154. Assume that mass M is in equilibrium :

Find the acceleration of the prism of mass M and that of the bar of mass m shown in figure.

A block of mass m is at rest on a rought wedge as shown in figure. What is the force exerted by the wedge on the block?

A system of men and trolley is shown in Fig. To the left, end of the string, a trolley of mass M is connected on which a man of mass m is standing. To the right end of the string another trolley of mass m is connected on which a man of mass M is standing. Initially, the system is at rest. All of a sudden both the men leap upwards simultaneously with the same velocity u w.r.t. ground. Find the relative velocity of left man with respect to his trolley just after he leaps upwards.

All the surfaces are smooth as shown in figure. The acceleration of mass m relative to wedge is :

A man of mass 60kg is standing on a massless weighing machine. Find the weight of the man in different situations as shown in the following figures. Man holds the rope and the block is at rest. Man holds the rope and the system is at rest. Man holds the rope and the system is at rest.

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a= 2 m//s^(2), v = - 2 m//s

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = 2m//s^(2) , v = 2 m//s

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = - 2 m//s^(2) , v= - 2 m//s