Figure-2.64 shows a block of mass M supporting a bar of mass m through a pulley system. If system is released from rest, find the acceleration of block M and the tension in the strings

Figure-2.54 shows a block of mass m is placed on an inclined wedge of mass M If the system is released from rest find the acceleration of m and M.

The system shown in figure is released is released from rest . Find acceleration of different string blocks and tenson in different strings.

The block of mass m is at rest. Find the tension in the string A .

The pulley is light and smooth : the strings are inextensible and light. The system is released from rest, find the acceleration of each block, tensions in the strings and reaction in pulley.

Figure shows a block of mass m_(1) sliding on a block of mass m_(2) , with m_(1) gt m_(2) . Find the (a) acceleration of each block (b) tension in the string (c ) force exerted by m_(1) on m_(2) . ltbr. (d) force exerted by m_(2) on the incline.

Two blocks are connected by a string that passes over a pulley of radius R and moment of inertia I . The block of mass m_(1) sides on a frictionless, horizontal surface, the block of mass m_(2) is suspended from the string. Find the acceleration a of the blocks and the tension T_(1) and T_(2) assuming that the string does not slip on the pulley.

Block A of mass m and block B of mass 2m are placed on a fixed triangular wedge by means of a light and inextensible string and a frictionless pulley as shown in fig . The wedge is inclined at 45^(@) to the horizontal on both sides . The coefficient of friction between the block A and the wedge is 2//3 and that between the block B and the wedge is 1//3 .If the system of A and B is released from rest then find . a. the acceleration of A b. tension in the string c.the magnitude and direction of the frictional force acting on A

A block of mass M is placed on the top of a bigger block of mass 10 M as shown in figure. All the surfaces are frictionless. The system is released from rest, then the distance moved by the bigger block at the instant the smaller block reaches the ground :