Home
Class 11
PHYSICS
A 40 kg slb rest on a frictionless floor...


A 40 kg slb rest on a frictionless floor as shown in the figure. A 10 kg block rests on the top of the slab. The static corfficient of friction between the block and slab is 0.60 while the kinetic friction is 0.40 the 10 kg block is acted upon by a horizontal force 100N. If `g=9.8(m)/(s^2)`, the resulting acceleration of the slab will be.

A

`1 m//s^(2)`

B

`1.47 m//s^(2)`

C

`1.52 m//s^(2)`

D

`6.1 m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • NEWTONS LAWS OF MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Advance MCQs|17 Videos

  • NEWTONS LAWS OF MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numerical Problem|81 Videos

  • NEWTONS LAWS OF MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Conceptual MCQs|23 Videos

  • LINEAR MOMENTUM & ITS CONSERVATION

    PHYSICS GALAXY - ASHISH ARORA|Exercise exercise 1.3|3 Videos

  • RIGID BODIES AND ROTATIONAL MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numerical|63 Videos

Similar Questions

Explore conceptually related problems

A 40kg slab rests on a frictionless floor as shown in the figure. A 10kg block rests on the top of the slab. The static coefficient of friction between the block and slab is 0.60 while the kinetic friction is 0.04 . The 10kg block is acted upon by a horizontal force 100N. if g=9.8m//s^(2) , the resulting acceleration of the slab will be.

A 40 kg slab rests on a frictionless floor . A 10 kg block rests on top of the slab (Fig . 7. 121). The static coefficient of friction between the block and the slab is 0.60 while the kinetic coefficient is 0.40 . The 10 kg block is acted upon by a horizontal force of 100 N . if g = 9.8 m//s^(2) the resulting acceleration of the slab will be :

A 40 kg slab rests on a frictionless floor. A 10 kg block rests on top of the slab. The coefficient of friction between the block and the slab is 0.40. The 10 kg block is acted upon by a horizontal force of 100 N. If g=10m//s^(2) , the resulting acceleration of the slab will be

A 40 kg slab rests on a frictionless floor . A 10 kg block rests on the top of the slab . [Fig. 7.81 (a)] . The coefficients of static and dynamic friction are 0.60 and 0.40 respectively . The 10 kg block is pulled by a horizontal force of 100 N . what are the resulting accelerations of (a) the block (b) the slab ? ( g = 10 m// s^(2) )

A force of 200N is applied as shown in the figure on block of 3 kg. The coefficient of friction between the block and the wall is 0.3. Find the friction acting on the block. (in N) {Take g = 10 m//s^(2)

In the arrangement shown in figure coefficient of friction between 5kg block and incline plane is mu=0.5 . Friction force acting on the 5kg block is

Block A of mass 5 kg is resting on a frictionless floor. Another block B of mass 7kg is resting on it as shown in the figure. The coefficient of friction between the blocks is 0.5 while kinetic friction is 0.4. If a force of 100 N is applied to block B, the acceleration of the block A will be ( g =10 ms^(-2)) :

Consider the shown arrangement. The coefficient of friction between the two blocks is 0.5 . There is no friction between the 4 kg block and of 12 N is applied on the 2 kg block as shown in the figure, the acceleration of the 4 kg block would be

PHYSICS GALAXY - ASHISH ARORA-NEWTONS LAWS OF MOTION-Numerical MCQs
  1. A block is given certain upward velocity along the incline of elevatio...

    Text Solution

    |

  2. Consider the shown arrangement. The coefficient of friction between th...

    Text Solution

    |

  3. A 40 kg slb rest on a frictionless floor as shown in the figure. A 10 ...

    Text Solution

    |

  4. A load attached to the end of a spring and in equilibrium produces 9 c...

    Text Solution

    |

  5. A heavy spherical ball is constrained in a frame as shown in figure-2....

    Text Solution

    |

  6. Find the reading of spring balance as shown in figure-2.154. Assume th...

    Text Solution

    |

  7. For what value of M will the masses be in equilibrium. Masses are plac...

    Text Solution

    |

  8. A body of mass m starts sliding down an incline of 30^(@) from rest. ...

    Text Solution

    |

  9. A mass of 0.5 kg is just able to slide down the slope of an inclined r...

    Text Solution

    |

  10. Minimum force required to keep a block of mass 1 kg at rest against a ...

    Text Solution

    |

  11. A 60 kg body is pushed with just enough force to start it moving acros...

    Text Solution

    |

  12. A particle of small m is joined to a very heavy body by a light string...

    Text Solution

    |

  13. A 20 kg monkey slides down a vertical rope with a constant acceleratio...

    Text Solution

    |

  14. A block A of mass 2 kg rests on another block B of mass 8 kg which res...

    Text Solution

    |

  15. A man slides down a light rope whose breaking strength in eta times hi...

    Text Solution

    |

  16. A string of negligible mass going over a clamped pulley of mass m supp...

    Text Solution

    |

  17. A mass m rests under the action of a force F as shown in the figure-2....

    Text Solution

    |

  18. A block of mass 0.1 is held against a wall applying a horizontal force...

    Text Solution

    |

  19. A block of mass M = 4 kg is kept on a smooth horizontal plane. A bar o...

    Text Solution

    |

  20. If Newton is redefined as the force of attraction between two masses (...

    Text Solution

    |