The emf `varepsilon` of a Cu-Fe thermocouple varies with the temperature `theta` of the hot junction (cold junction at `0^(@)C` ), as `varepsilon(mu V)=14 theta-0.02 theta^(2)` Determine the neutral temperature.

Thermo e.m.f. E of a Cu-Fe thermocouple varies with the temperature theta of the hot junction ( cold juction 0^(@)C ) as E(muV)=12theta-0.02 theta^(2) . Determine:- (a) Neutral temperature of the termocouple (b) Temperature of inversion, assuming that cold junction is at 20^(@)C . (c) Value of Seebeck coefficient at neutral temperature

For Copper-iron (Cu-Fe) couple, the thermo e.m.f. (temperature of cold junction =^(@)C ) is given by E=(14theta-0.02 theta^(2) ) mu V . The neutral temperature will be

The thermo emf of thermocouple varies with the temperature theta of the hot junction as E = atheta + btheta^2 in volts where the ratio a//b is 700^@C . If the cold junction is kept at 0^@C , then the neutral temperature is

The thermo emf E of a thermocouple is found to vary wit temperature T of the junction (cold junction is 0^(@)C ) as E=40T-(T^(2))/(20) The temperature of inversion for the thermocouple is

For a copper-iron and a chromel-alumel thermocouple, the plots between thermoelectric emf and the temperature theta of the hot junction (when the cold junction is at 0^(@)C )are found to satisfy approximately the parabola equation V=alpha theta+(1)/(2)betatheta^(2) with alpha=14muV^(@)C^(-1) beta=-0.04V^(@)C^(-2) (copper-iron) alpha=41muCV^(@)C^(-1),beta=-0.002V^(@)C^(-2) (chromel-alumel) Which of the two thermocouples would you use to measure temperature in the range of a about 500^(@)C to 600^(@)C ?

The thermo e.m.f. E in volts of a certain thermocouple is found to vary with temperature difference q in .^(@)C between the two junctions according to the relation E=30 theta-(theta^(2))/(15) The neutral temperature for the thermo-couple will be:-

The thermo e.m.f E in volts of a certain thermocouple is found to very with temperature difference theta in ""^(@)C between the two junctions according to the relation E = 30 theta - (theta^(2))/(15) . The neutral temperatur e for the thermo - couple will be .

The cold junction of a thermocouple is at 0^(@)C . The thermo e.m.f. epsilon , in volts, generated in this thermocouple varies with temperature t^(@)C of the hot junction as epsilon=6+4t-(t^(2))/(32) . The neutral temperature of the thermocouple

If the emf of a thermocouple, one junction of which is kep 0^(@)C is given by e=at+1//2bt^(2) then the neutral temperature will be