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For a Cu-Fe thermocouple, nertral temper...

For a Cu-Fe thermocouple, nertral temperature is `270^(@)C`. If `alpha=15.86 mu V.^(@)V^(-1)` then find the value of `beta`

Text Solution

Verified by Experts

The correct Answer is:
`-0.0587 mu V .^(@)C^(-2)`
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