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For a certain thermocouple , varepsilon=...

For a certain thermocouple , `varepsilon=alphatheta+(1)/(2)betatheta^(@),where theta.^(@)C` is the temperature of the hot junction and `0^(@)C` is the temperature of the cold junction . If `alpha =10 mu V.^(@)C^(-1)` and `beta=-(1)/(20)muV.^(@)C^(-2)`, find the neutral temperature and temperature of inversion.

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The correct Answer is:
`200^(@)C , 400.^(@)C`
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